Mixed Topic Worksheet Grades 8/9: Day 075
- 1
Question 1. Write down the coordinates of the minimum point of the graph of y = 3sin x for 0° ≤ x ≤ 360°.
Transforming Trigonometric Graphs▶ Show worked answerHide worked answer
- B1: x = 270°
- B1: y = -3
Answer: (270°, -3)[2 marks] - 2
Question 2. The graph of y = f(x + 2) - 1 has a minimum point at (0, 3). Write down the coordinates of the minimum point of the graph of y = f(x)
Translations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: f(x + 2) moves the graph 2 left and -1 moves it 1 down, so y = f(x) is 2 right and 1 up
- A1: (2, 4)
Answer: (2, 4)[2 marks] - 3
Question 3. Simplify dfrac√80 + √20√5.
Simplifying Surds▶ Show worked answerHide worked answer
- M1: √80 = 4√5 and √20 = 2√5
- M1: dfrac6√5√5
- A1: 6
Answer: 6[3 marks] - 4
Question 4. PA and PB are tangents to a circle with centre O, touching it at A and B. Angle AOB = 124°. Work out the size of angle APB. Give reasons.
Circle Theorems▶ Show worked answerHide worked answer
- B1: angles OAP and OBP are 90° (tangent and radius)
- M1: 360 - 90 - 90 - 124
- A1: 56° (angles in a quadrilateral)
Answer: 56°[3 marks] - 5
Question 5. 2x² + bx + 27 equiv 2(x + p)² - 5
b is a positive number
Work out the value of b and the value of pSolving Quadratics by Completing the Square (a > 1)▶ Show worked answerHide worked answer
- M1: expand: 2(x² + 2px + p²) - 5 = 2x² + 4px + 2p² - 5
- M1: 2p² - 5 = 27
- A1: p = 4
- A1: b = 16
Answer: b = 16, p = 4[4 marks]
Mixed Topic Worksheet Grades 8/9: Day 075
- 1
Question 1. Write down the coordinates of the minimum point of the graph of y = 3sin x for 0° ≤ x ≤ 360°.
[2 marks]Transforming Trigonometric Graphs▶ Show worked answerHide worked answer
- B1: x = 270°
- B1: y = -3
Answer: (270°, -3) - 2
Question 2. The graph of y = f(x + 2) - 1 has a minimum point at (0, 3). Write down the coordinates of the minimum point of the graph of y = f(x)
[2 marks]Translations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: f(x + 2) moves the graph 2 left and -1 moves it 1 down, so y = f(x) is 2 right and 1 up
- A1: (2, 4)
Answer: (2, 4) - 3
Question 3. Simplify dfrac√80 + √20√5.
[3 marks]Simplifying Surds▶ Show worked answerHide worked answer
- M1: √80 = 4√5 and √20 = 2√5
- M1: dfrac6√5√5
- A1: 6
Answer: 6 - 4
Question 4. PA and PB are tangents to a circle with centre O, touching it at A and B. Angle AOB = 124°. Work out the size of angle APB. Give reasons.
[3 marks]Circle Theorems▶ Show worked answerHide worked answer
- B1: angles OAP and OBP are 90° (tangent and radius)
- M1: 360 - 90 - 90 - 124
- A1: 56° (angles in a quadrilateral)
Answer: 56° - 5
Question 5. 2x² + bx + 27 equiv 2(x + p)² - 5
[4 marks]
b is a positive number
Work out the value of b and the value of pSolving Quadratics by Completing the Square (a > 1)▶ Show worked answerHide worked answer
- M1: expand: 2(x² + 2px + p²) - 5 = 2x² + 4px + 2p² - 5
- M1: 2p² - 5 = 27
- A1: p = 4
- A1: b = 16
Answer: b = 16, p = 4
Mixed Topic Worksheet Grades 8/9: Day 075
- 1
Question 1. Write down the coordinates of the minimum point of the graph of y = 3sin x for 0° ≤ x ≤ 360°.
Transforming Trigonometric Graphs▶ Show worked answerHide worked answer
- B1: x = 270°
- B1: y = -3
Answer: (270°, -3)[2 marks] - 2
Question 2. The graph of y = f(x + 2) - 1 has a minimum point at (0, 3). Write down the coordinates of the minimum point of the graph of y = f(x)
Translations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: f(x + 2) moves the graph 2 left and -1 moves it 1 down, so y = f(x) is 2 right and 1 up
- A1: (2, 4)
Answer: (2, 4)[2 marks] - 3
Question 3. Simplify dfrac√80 + √20√5.
Simplifying Surds▶ Show worked answerHide worked answer
- M1: √80 = 4√5 and √20 = 2√5
- M1: dfrac6√5√5
- A1: 6
Answer: 6[3 marks] - 4
Question 4. PA and PB are tangents to a circle with centre O, touching it at A and B. Angle AOB = 124°. Work out the size of angle APB. Give reasons.
Circle Theorems▶ Show worked answerHide worked answer
- B1: angles OAP and OBP are 90° (tangent and radius)
- M1: 360 - 90 - 90 - 124
- A1: 56° (angles in a quadrilateral)
Answer: 56°[3 marks] - 5
Question 5. 2x² + bx + 27 equiv 2(x + p)² - 5
b is a positive number
Work out the value of b and the value of pSolving Quadratics by Completing the Square (a > 1)▶ Show worked answerHide worked answer
- M1: expand: 2(x² + 2px + p²) - 5 = 2x² + 4px + 2p² - 5
- M1: 2p² - 5 = 27
- A1: p = 4
- A1: b = 16
Answer: b = 16, p = 4[4 marks]