Mixed Topic Worksheet Grades 8/9: Day 070
- 1
Question 1. Solve 7sin x + 2 = 0 for 0^° ≤ x ≤ 360^°. Give your answers correct to 1 decimal place.
Solving Trigonometric Equations Using a Graph▶ Show worked answerHide worked answer
- M1: sin x = -2/7, so the acute angle is sin⁻¹2/7
- A1: x = 196.6^° and x = 343.4^°
Answer: x = 196.6^° and x = 343.4^°[2 marks] - 2
Question 2. Write x² + 12x - 5 in the form (x + a)² + b.
Solving Quadratics by Completing the Square (a = 1)▶ Show worked answerHide worked answer
- M1: (x + 6)²
- A1: (x + 6)² - 41
Answer: (x + 6)² - 41[2 marks] - 3
Question 3. Show that the equation 2x + x = 10 has a solution between x = 2.8 and x = 2.9
Change of Signs▶ Show worked answerHide worked answer
- M1: f(x) = 2x + x - 10, work out f(2.8) and f(2.9)
- M1: f(2.8) = -0.236 < 0 and f(2.9) = 0.364 > 0, sign change
Answer: Shown[2 marks] - 4
Question 4. PT is a tangent to a circle, centre O, at T.
Angle OPT = 24^°.
Work out angle POT. Give reasons. [3]Combining Circle Theorems▶ Show worked answerHide worked answer
- B1: angle OTP = 90^° (tangent is perpendicular to the radius)
- M1: angles in a triangle sum to 180^°: 180 - 90 - 24
- A1: 66^°
Answer: 66^°[3 marks] - 5
Question 5. The circle C, centre O, has equation x² + y² = 80
The tangent to C at the point P has gradient -2
P lies in the first quadrant.
Work out the coordinates of P.Finding Equations of Tangents to Circles▶ Show worked answerHide worked answer
- M1: m_OP = dfrac12, so P lies on y = dfrac12x
- M1: x² + ≤ft(dfracx2)² = 80, giving x² = 64
- A1: (8, 4)
Answer: (8, 4)[3 marks]
Mixed Topic Worksheet Grades 8/9: Day 070
- 1
Question 1. Solve 7sin x + 2 = 0 for 0^° ≤ x ≤ 360^°. Give your answers correct to 1 decimal place.
[2 marks]Solving Trigonometric Equations Using a Graph▶ Show worked answerHide worked answer
- M1: sin x = -2/7, so the acute angle is sin⁻¹2/7
- A1: x = 196.6^° and x = 343.4^°
Answer: x = 196.6^° and x = 343.4^° - 2
Question 2. Write x² + 12x - 5 in the form (x + a)² + b.
[2 marks]Solving Quadratics by Completing the Square (a = 1)▶ Show worked answerHide worked answer
- M1: (x + 6)²
- A1: (x + 6)² - 41
Answer: (x + 6)² - 41 - 3
Question 3. Show that the equation 2x + x = 10 has a solution between x = 2.8 and x = 2.9
[2 marks]Change of Signs▶ Show worked answerHide worked answer
- M1: f(x) = 2x + x - 10, work out f(2.8) and f(2.9)
- M1: f(2.8) = -0.236 < 0 and f(2.9) = 0.364 > 0, sign change
Answer: Shown - 4
Question 4. PT is a tangent to a circle, centre O, at T.
[3 marks]
Angle OPT = 24^°.
Work out angle POT. Give reasons. [3]Combining Circle Theorems▶ Show worked answerHide worked answer
- B1: angle OTP = 90^° (tangent is perpendicular to the radius)
- M1: angles in a triangle sum to 180^°: 180 - 90 - 24
- A1: 66^°
Answer: 66^° - 5
Question 5. The circle C, centre O, has equation x² + y² = 80
[3 marks]
The tangent to C at the point P has gradient -2
P lies in the first quadrant.
Work out the coordinates of P.Finding Equations of Tangents to Circles▶ Show worked answerHide worked answer
- M1: m_OP = dfrac12, so P lies on y = dfrac12x
- M1: x² + ≤ft(dfracx2)² = 80, giving x² = 64
- A1: (8, 4)
Answer: (8, 4)
Mixed Topic Worksheet Grades 8/9: Day 070
- 1
Question 1. Solve 7sin x + 2 = 0 for 0^° ≤ x ≤ 360^°. Give your answers correct to 1 decimal place.
Solving Trigonometric Equations Using a Graph▶ Show worked answerHide worked answer
- M1: sin x = -2/7, so the acute angle is sin⁻¹2/7
- A1: x = 196.6^° and x = 343.4^°
Answer: x = 196.6^° and x = 343.4^°[2 marks] - 2
Question 2. Write x² + 12x - 5 in the form (x + a)² + b.
Solving Quadratics by Completing the Square (a = 1)▶ Show worked answerHide worked answer
- M1: (x + 6)²
- A1: (x + 6)² - 41
Answer: (x + 6)² - 41[2 marks] - 3
Question 3. Show that the equation 2x + x = 10 has a solution between x = 2.8 and x = 2.9
Change of Signs▶ Show worked answerHide worked answer
- M1: f(x) = 2x + x - 10, work out f(2.8) and f(2.9)
- M1: f(2.8) = -0.236 < 0 and f(2.9) = 0.364 > 0, sign change
Answer: Shown[2 marks] - 4
Question 4. PT is a tangent to a circle, centre O, at T.
Angle OPT = 24^°.
Work out angle POT. Give reasons. [3]Combining Circle Theorems▶ Show worked answerHide worked answer
- B1: angle OTP = 90^° (tangent is perpendicular to the radius)
- M1: angles in a triangle sum to 180^°: 180 - 90 - 24
- A1: 66^°
Answer: 66^°[3 marks] - 5
Question 5. The circle C, centre O, has equation x² + y² = 80
The tangent to C at the point P has gradient -2
P lies in the first quadrant.
Work out the coordinates of P.Finding Equations of Tangents to Circles▶ Show worked answerHide worked answer
- M1: m_OP = dfrac12, so P lies on y = dfrac12x
- M1: x² + ≤ft(dfracx2)² = 80, giving x² = 64
- A1: (8, 4)
Answer: (8, 4)[3 marks]