Mixed Topic Worksheet Grades 8/9: Day 036
- 1
Question 1. Solve sin x = -0.35 for -180^° ≤ x ≤ 180^°. Give your answers correct to 1 decimal place
Solving Trigonometric Equations Using a Graph▶ Show worked answerHide worked answer
- M1: x = sin⁻¹(-0.35)
- M1: second solution is -180^° minus the first
- A1: -20.5^° and -159.5^°
Answer: x = -20.5^° and x = -159.5^°[3 marks] - 2
Question 2. PT is a tangent to a circle with centre O, touching it at T. OT = 5 cm and PT = 12 cm. Work out the size of angle TPO. Give your answer correct to 1 decimal place.
Circle Theorems▶ Show worked answerHide worked answer
- B1: angle OTP = 90° (tangent meets radius at right angle)
- M1: tan TPO = dfrac512
- A1: 22.6°
Answer: 22.6°[3 marks] - 3
Question 3. Use a change of sign to show that sqrt[3]20 is 2.7 correct to 1 decimal place
Change of Signs▶ Show worked answerHide worked answer
- M1: f(x) = x³ - 20, work out f(x) at the ends of the range
- M1: f(2.65) = -1.39... and f(2.75) = 0.797...
- C1: sign change so sqrt[3]20 is between 2.65 and 2.75, which is 2.7
Answer: Shown: between 2.65 and 2.75[3 marks] - 4
Question 4. The graph of y = x² - 6x + 5 is translated by the vector beginpmatrix 2 -3 endpmatrix
Work out the coordinates of the turning point of the translated graph.Translations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: x² - 6x + 5 = (x - 3)² - 4
- A1: turning point of the original graph (3, -4)
- M1: add 2 to x and subtract 3 from y
- A1: (5, -7)
Answer: (5, -7)[4 marks] - 5
Question 5. Write dfrac√3√3 - 2 in the form a + b√3 where a and b are integers.
Rationalising Denominators of the Form a ± √b▶ Show worked answerHide worked answer
- M1: multiply top and bottom by √3 + 2
- M1: dfrac3 + 2√33 - 4
- A1: -3 - 2√3
Answer: -3 - 2√3[3 marks]
Mixed Topic Worksheet Grades 8/9: Day 036
- 1
Question 1. Solve sin x = -0.35 for -180^° ≤ x ≤ 180^°. Give your answers correct to 1 decimal place
[3 marks]Solving Trigonometric Equations Using a Graph▶ Show worked answerHide worked answer
- M1: x = sin⁻¹(-0.35)
- M1: second solution is -180^° minus the first
- A1: -20.5^° and -159.5^°
Answer: x = -20.5^° and x = -159.5^° - 2
Question 2. PT is a tangent to a circle with centre O, touching it at T. OT = 5 cm and PT = 12 cm. Work out the size of angle TPO. Give your answer correct to 1 decimal place.
[3 marks]Circle Theorems▶ Show worked answerHide worked answer
- B1: angle OTP = 90° (tangent meets radius at right angle)
- M1: tan TPO = dfrac512
- A1: 22.6°
Answer: 22.6° - 3
Question 3. Use a change of sign to show that sqrt[3]20 is 2.7 correct to 1 decimal place
[3 marks]Change of Signs▶ Show worked answerHide worked answer
- M1: f(x) = x³ - 20, work out f(x) at the ends of the range
- M1: f(2.65) = -1.39... and f(2.75) = 0.797...
- C1: sign change so sqrt[3]20 is between 2.65 and 2.75, which is 2.7
Answer: Shown: between 2.65 and 2.75 - 4
Question 4. The graph of y = x² - 6x + 5 is translated by the vector beginpmatrix 2 -3 endpmatrix
[4 marks]
Work out the coordinates of the turning point of the translated graph.Translations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: x² - 6x + 5 = (x - 3)² - 4
- A1: turning point of the original graph (3, -4)
- M1: add 2 to x and subtract 3 from y
- A1: (5, -7)
Answer: (5, -7) - 5
Question 5. Write dfrac√3√3 - 2 in the form a + b√3 where a and b are integers.
[3 marks]Rationalising Denominators of the Form a ± √b▶ Show worked answerHide worked answer
- M1: multiply top and bottom by √3 + 2
- M1: dfrac3 + 2√33 - 4
- A1: -3 - 2√3
Answer: -3 - 2√3
Mixed Topic Worksheet Grades 8/9: Day 036
- 1
Question 1. Solve sin x = -0.35 for -180^° ≤ x ≤ 180^°. Give your answers correct to 1 decimal place
Solving Trigonometric Equations Using a Graph▶ Show worked answerHide worked answer
- M1: x = sin⁻¹(-0.35)
- M1: second solution is -180^° minus the first
- A1: -20.5^° and -159.5^°
Answer: x = -20.5^° and x = -159.5^°[3 marks] - 2
Question 2. PT is a tangent to a circle with centre O, touching it at T. OT = 5 cm and PT = 12 cm. Work out the size of angle TPO. Give your answer correct to 1 decimal place.
Circle Theorems▶ Show worked answerHide worked answer
- B1: angle OTP = 90° (tangent meets radius at right angle)
- M1: tan TPO = dfrac512
- A1: 22.6°
Answer: 22.6°[3 marks] - 3
Question 3. Use a change of sign to show that sqrt[3]20 is 2.7 correct to 1 decimal place
Change of Signs▶ Show worked answerHide worked answer
- M1: f(x) = x³ - 20, work out f(x) at the ends of the range
- M1: f(2.65) = -1.39... and f(2.75) = 0.797...
- C1: sign change so sqrt[3]20 is between 2.65 and 2.75, which is 2.7
Answer: Shown: between 2.65 and 2.75[3 marks] - 4
Question 4. The graph of y = x² - 6x + 5 is translated by the vector beginpmatrix 2 -3 endpmatrix
Work out the coordinates of the turning point of the translated graph.Translations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: x² - 6x + 5 = (x - 3)² - 4
- A1: turning point of the original graph (3, -4)
- M1: add 2 to x and subtract 3 from y
- A1: (5, -7)
Answer: (5, -7)[4 marks] - 5
Question 5. Write dfrac√3√3 - 2 in the form a + b√3 where a and b are integers.
Rationalising Denominators of the Form a ± √b▶ Show worked answerHide worked answer
- M1: multiply top and bottom by √3 + 2
- M1: dfrac3 + 2√33 - 4
- A1: -3 - 2√3
Answer: -3 - 2√3[3 marks]