Mixed Topic Worksheet Grades 8/9: Day 010
- 1
Question 1. The graph of y = 2sin(x + 30^°) + 1 is drawn. Work out the value of y when x = 100^°. Give your answer correct to 3 significant figures.
Transforming Trigonometric Graphs▶ Show worked answerHide worked answer
- M1: y = 2sin 130^° + 1
- A1: 2.53
Answer: 2.53[2 marks] - 2
Question 2. A rectangle has an area of 18 cm² and a length of √12 cm. Work out the width of the rectangle, giving your answer in the form a√b where a and b are integers and b is as small as possible.
Rationalising Denominators of the Form √a▶ Show worked answerHide worked answer
- M1: dfrac18√12 = dfrac182√3 = dfrac9√3
- M1: dfrac9√33
- A1: 3√3 cm
Answer: 3√3 cm[3 marks] - 3
Question 3. Solve x² - 10x + 5 = 0 by completing the square
Give the solutions in the form a ± b√c where a, b and c are integers.Solving Quadratics by Completing the Square (a = 1)▶ Show worked answerHide worked answer
- M1: (x - 5)² - 25 + 5 = 0
- M1: (x - 5)² = 20
- M1: x - 5 = ±√20 and √20 = 2√5
- A1: x = 5 ± 2√5
Answer: x = 5 ± 2√5[4 marks] - 4
Question 4. The graph of y = x² - 3x is translated by the vector beginpmatrix -1 4 endpmatrix
Find the equation of the translated graph.
Give your answer in the form y = x² + bx + cTranslations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: replace x with x + 1: (x + 1)² - 3(x + 1)
- M1: add 4: y = (x + 1)² - 3(x + 1) + 4
- M1: x² + 2x + 1 - 3x - 3 + 4
- A1: y = x² - x + 2
Answer: y = x² - x + 2[4 marks] - 5
Question 5. The point P(6, -3) lies on the circle x² + y² = 45
Find an equation of the tangent to the circle at P.Finding Equations of Tangents to Circles▶ Show worked answerHide worked answer
- M1: gradient of OP = -dfrac36 = -dfrac12
- M1: tangent gradient 2 and y + 3 = 2(x - 6)
- A1: y = 2x - 15
Answer: y = 2x - 15[3 marks]
Mixed Topic Worksheet Grades 8/9: Day 010
- 1
Question 1. The graph of y = 2sin(x + 30^°) + 1 is drawn. Work out the value of y when x = 100^°. Give your answer correct to 3 significant figures.
[2 marks]Transforming Trigonometric Graphs▶ Show worked answerHide worked answer
- M1: y = 2sin 130^° + 1
- A1: 2.53
Answer: 2.53 - 2
Question 2. A rectangle has an area of 18 cm² and a length of √12 cm. Work out the width of the rectangle, giving your answer in the form a√b where a and b are integers and b is as small as possible.
[3 marks]Rationalising Denominators of the Form √a▶ Show worked answerHide worked answer
- M1: dfrac18√12 = dfrac182√3 = dfrac9√3
- M1: dfrac9√33
- A1: 3√3 cm
Answer: 3√3 cm - 3
Question 3. Solve x² - 10x + 5 = 0 by completing the square
[4 marks]
Give the solutions in the form a ± b√c where a, b and c are integers.Solving Quadratics by Completing the Square (a = 1)▶ Show worked answerHide worked answer
- M1: (x - 5)² - 25 + 5 = 0
- M1: (x - 5)² = 20
- M1: x - 5 = ±√20 and √20 = 2√5
- A1: x = 5 ± 2√5
Answer: x = 5 ± 2√5 - 4
Question 4. The graph of y = x² - 3x is translated by the vector beginpmatrix -1 4 endpmatrix
[4 marks]
Find the equation of the translated graph.
Give your answer in the form y = x² + bx + cTranslations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: replace x with x + 1: (x + 1)² - 3(x + 1)
- M1: add 4: y = (x + 1)² - 3(x + 1) + 4
- M1: x² + 2x + 1 - 3x - 3 + 4
- A1: y = x² - x + 2
Answer: y = x² - x + 2 - 5
Question 5. The point P(6, -3) lies on the circle x² + y² = 45
[3 marks]
Find an equation of the tangent to the circle at P.Finding Equations of Tangents to Circles▶ Show worked answerHide worked answer
- M1: gradient of OP = -dfrac36 = -dfrac12
- M1: tangent gradient 2 and y + 3 = 2(x - 6)
- A1: y = 2x - 15
Answer: y = 2x - 15
Mixed Topic Worksheet Grades 8/9: Day 010
- 1
Question 1. The graph of y = 2sin(x + 30^°) + 1 is drawn. Work out the value of y when x = 100^°. Give your answer correct to 3 significant figures.
Transforming Trigonometric Graphs▶ Show worked answerHide worked answer
- M1: y = 2sin 130^° + 1
- A1: 2.53
Answer: 2.53[2 marks] - 2
Question 2. A rectangle has an area of 18 cm² and a length of √12 cm. Work out the width of the rectangle, giving your answer in the form a√b where a and b are integers and b is as small as possible.
Rationalising Denominators of the Form √a▶ Show worked answerHide worked answer
- M1: dfrac18√12 = dfrac182√3 = dfrac9√3
- M1: dfrac9√33
- A1: 3√3 cm
Answer: 3√3 cm[3 marks] - 3
Question 3. Solve x² - 10x + 5 = 0 by completing the square
Give the solutions in the form a ± b√c where a, b and c are integers.Solving Quadratics by Completing the Square (a = 1)▶ Show worked answerHide worked answer
- M1: (x - 5)² - 25 + 5 = 0
- M1: (x - 5)² = 20
- M1: x - 5 = ±√20 and √20 = 2√5
- A1: x = 5 ± 2√5
Answer: x = 5 ± 2√5[4 marks] - 4
Question 4. The graph of y = x² - 3x is translated by the vector beginpmatrix -1 4 endpmatrix
Find the equation of the translated graph.
Give your answer in the form y = x² + bx + cTranslations Along the x- & y-Axes▶ Show worked answerHide worked answer
- M1: replace x with x + 1: (x + 1)² - 3(x + 1)
- M1: add 4: y = (x + 1)² - 3(x + 1) + 4
- M1: x² + 2x + 1 - 3x - 3 + 4
- A1: y = x² - x + 2
Answer: y = x² - x + 2[4 marks] - 5
Question 5. The point P(6, -3) lies on the circle x² + y² = 45
Find an equation of the tangent to the circle at P.Finding Equations of Tangents to Circles▶ Show worked answerHide worked answer
- M1: gradient of OP = -dfrac36 = -dfrac12
- M1: tangent gradient 2 and y + 3 = 2(x - 6)
- A1: y = 2x - 15
Answer: y = 2x - 15[3 marks]