Mixed Topic Worksheet Grades 6/7: Day 094
- 1
Question 1. The mean mass of 6 bags is 12 kg.
A seventh bag is added and the mean mass of the 7 bags is 13 kg.
Work out the mass of the seventh bag.Reverse Mean from a List▶ Show worked answerHide worked answer
- M1: total of 7 bags 7 x 13 = 91, total of 6 bags 6 x 12 = 72
- M1: 91 - 72
- A1: 19 kg
Answer: 19 kg[3 marks] - 2
Question 2. A field is in the shape of a triangle.
Two sides of the field are 120 m and 85 m long.
The angle between these two sides is 58^°.
One bag of grass seed covers 600 m².
Work out the number of bags of grass seed needed to cover the field.Area of Triangles Using ½ab sin C▶ Show worked answerHide worked answer
- M1: area = 1/2 × 120 × 85 × sin 58^°
- M1: area ÷ 600 = 7.2
- A1: 8 bags (rounded up)
Answer: 8 bags[3 marks] - 3
Question 3. Sam thinks of an integer n. He adds 2 to the number and cubes the result. He then subtracts n³ and subtracts 8. Prove that Sam's final answer is a multiple of 6.
Proof with Multiples▶ Show worked answerHide worked answer
- M1: (n + 2)³ = n³ + 6n² + 12n + 8
- M1: (n + 2)³ - n³ - 8 = 6n² + 12n
- M1: 6n(n + 2)
- C1: a multiple of 6 for every integer n
Answer: 6n(n + 2), a multiple of 6[4 marks] - 4[1 mark]
- 5
Question 5. In triangle PQR, angle PRQ = 29^° and dfracPQsin 29^° = 13.6
Work out PQ. Give your answer to 1 decimal place.Fundamentals of the Sine Rule▶ Show worked answerHide worked answer
- M1: PQ = 13.6 × sin 29^°
- A1: 6.6
Answer: 6.6[2 marks]
Mixed Topic Worksheet Grades 6/7: Day 094
- 1
Question 1. The mean mass of 6 bags is 12 kg.
[3 marks]
A seventh bag is added and the mean mass of the 7 bags is 13 kg.
Work out the mass of the seventh bag.Reverse Mean from a List▶ Show worked answerHide worked answer
- M1: total of 7 bags 7 x 13 = 91, total of 6 bags 6 x 12 = 72
- M1: 91 - 72
- A1: 19 kg
Answer: 19 kg - 2
Question 2. A field is in the shape of a triangle.
[3 marks]
Two sides of the field are 120 m and 85 m long.
The angle between these two sides is 58^°.
One bag of grass seed covers 600 m².
Work out the number of bags of grass seed needed to cover the field.Area of Triangles Using ½ab sin C▶ Show worked answerHide worked answer
- M1: area = 1/2 × 120 × 85 × sin 58^°
- M1: area ÷ 600 = 7.2
- A1: 8 bags (rounded up)
Answer: 8 bags - 3
Question 3. Sam thinks of an integer n. He adds 2 to the number and cubes the result. He then subtracts n³ and subtracts 8. Prove that Sam's final answer is a multiple of 6.
[4 marks]Proof with Multiples▶ Show worked answerHide worked answer
- M1: (n + 2)³ = n³ + 6n² + 12n + 8
- M1: (n + 2)³ - n³ - 8 = 6n² + 12n
- M1: 6n(n + 2)
- C1: a multiple of 6 for every integer n
Answer: 6n(n + 2), a multiple of 6 - 4
Question 4. Work out 125¹/³
[1 mark]Fractional Powers▶ Show worked answerHide worked answer
- B1: 5
Answer: 5 - 5
Question 5. In triangle PQR, angle PRQ = 29^° and dfracPQsin 29^° = 13.6
[2 marks]
Work out PQ. Give your answer to 1 decimal place.Fundamentals of the Sine Rule▶ Show worked answerHide worked answer
- M1: PQ = 13.6 × sin 29^°
- A1: 6.6
Answer: 6.6
Mixed Topic Worksheet Grades 6/7: Day 094
- 1
Question 1. The mean mass of 6 bags is 12 kg.
A seventh bag is added and the mean mass of the 7 bags is 13 kg.
Work out the mass of the seventh bag.Reverse Mean from a List▶ Show worked answerHide worked answer
- M1: total of 7 bags 7 x 13 = 91, total of 6 bags 6 x 12 = 72
- M1: 91 - 72
- A1: 19 kg
Answer: 19 kg[3 marks] - 2
Question 2. A field is in the shape of a triangle.
Two sides of the field are 120 m and 85 m long.
The angle between these two sides is 58^°.
One bag of grass seed covers 600 m².
Work out the number of bags of grass seed needed to cover the field.Area of Triangles Using ½ab sin C▶ Show worked answerHide worked answer
- M1: area = 1/2 × 120 × 85 × sin 58^°
- M1: area ÷ 600 = 7.2
- A1: 8 bags (rounded up)
Answer: 8 bags[3 marks] - 3
Question 3. Sam thinks of an integer n. He adds 2 to the number and cubes the result. He then subtracts n³ and subtracts 8. Prove that Sam's final answer is a multiple of 6.
Proof with Multiples▶ Show worked answerHide worked answer
- M1: (n + 2)³ = n³ + 6n² + 12n + 8
- M1: (n + 2)³ - n³ - 8 = 6n² + 12n
- M1: 6n(n + 2)
- C1: a multiple of 6 for every integer n
Answer: 6n(n + 2), a multiple of 6[4 marks] - 4[1 mark]
- 5
Question 5. In triangle PQR, angle PRQ = 29^° and dfracPQsin 29^° = 13.6
Work out PQ. Give your answer to 1 decimal place.Fundamentals of the Sine Rule▶ Show worked answerHide worked answer
- M1: PQ = 13.6 × sin 29^°
- A1: 6.6
Answer: 6.6[2 marks]