Mixed Topic Worksheet Grades 6/7: Day 034
- 1
Question 1. Here is a right-angled triangle TUV.
Work out the value of x.
Give your answer to 1 decimal place.Finding Angles Using SOH, CAH, TOA▶ Show worked answerHide worked answer
- M1: sin 36° = 5.8/x
- M1: x = 5.8 ÷ sin 36°
- A1: 9.9
Answer: 9.9 cm[3 marks] - 2
Question 2. An extra value of 50 is added to the data 4, 6, 7, 9, 10, 12. Work out the interquartile range before and after, and the range before and after.
Benefits of IQR & Range▶ Show worked answerHide worked answer
- B1: IQR before: 10 - 6 = 4 and range 12 - 4 = 8
- B1: IQR after (4, 6, 7, 9, 10, 12, 50): 12 - 6 = 6 and range 50 - 4 = 46
Answer: IQR: before 4, after 6; range: before 8, after 46[2 marks] - 3
Question 3. 3(n + 2) + k(n + 9) is a multiple of 7 for all integer values of n.
k is a positive integer less than 7.
Work out the value of k.Proof with Multiples▶ Show worked answerHide worked answer
- M1: 3n + 6 + kn + 9k = (3 + k)n + 6 + 9k
- M1: 3 + k is a multiple of 7
- A1: k = 4
Answer: k = 4[3 marks] - 4
Question 4. Expand and simplify (2 + √3)(5 - √3)
Expanding Brackets with Surds▶ Show worked answerHide worked answer
- M1: four terms 10 - 2√3 + 5√3 - 3
- A1: 7 + 3√3
Answer: 7 + 3√3[2 marks] - 5
Question 5. A=x : 3(x-2)<12, x is an integer and B=x : x ≥ -1, x is an integer. Work out n(A cap B).
Sets & Inequalities▶ Show worked answerHide worked answer
- M1: x-2<4, so x<6
- M1: A cap B=-1, 0, 1, 2, 3, 4, 5
- A1: 7
Answer: 7[3 marks]
Mixed Topic Worksheet Grades 6/7: Day 034
- 1
Question 1. Here is a right-angled triangle TUV.
[3 marks]
Work out the value of x.
Give your answer to 1 decimal place.Finding Angles Using SOH, CAH, TOA▶ Show worked answerHide worked answer
- M1: sin 36° = 5.8/x
- M1: x = 5.8 ÷ sin 36°
- A1: 9.9
Answer: 9.9 cm - 2
Question 2. An extra value of 50 is added to the data 4, 6, 7, 9, 10, 12. Work out the interquartile range before and after, and the range before and after.
[2 marks]Benefits of IQR & Range▶ Show worked answerHide worked answer
- B1: IQR before: 10 - 6 = 4 and range 12 - 4 = 8
- B1: IQR after (4, 6, 7, 9, 10, 12, 50): 12 - 6 = 6 and range 50 - 4 = 46
Answer: IQR: before 4, after 6; range: before 8, after 46 - 3
Question 3. 3(n + 2) + k(n + 9) is a multiple of 7 for all integer values of n.
[3 marks]
k is a positive integer less than 7.
Work out the value of k.Proof with Multiples▶ Show worked answerHide worked answer
- M1: 3n + 6 + kn + 9k = (3 + k)n + 6 + 9k
- M1: 3 + k is a multiple of 7
- A1: k = 4
Answer: k = 4 - 4
Question 4. Expand and simplify (2 + √3)(5 - √3)
[2 marks]Expanding Brackets with Surds▶ Show worked answerHide worked answer
- M1: four terms 10 - 2√3 + 5√3 - 3
- A1: 7 + 3√3
Answer: 7 + 3√3 - 5
Question 5. A=x : 3(x-2)<12, x is an integer and B=x : x ≥ -1, x is an integer. Work out n(A cap B).
[3 marks]Sets & Inequalities▶ Show worked answerHide worked answer
- M1: x-2<4, so x<6
- M1: A cap B=-1, 0, 1, 2, 3, 4, 5
- A1: 7
Answer: 7
Mixed Topic Worksheet Grades 6/7: Day 034
- 1
Question 1. Here is a right-angled triangle TUV.
Work out the value of x.
Give your answer to 1 decimal place.Finding Angles Using SOH, CAH, TOA▶ Show worked answerHide worked answer
- M1: sin 36° = 5.8/x
- M1: x = 5.8 ÷ sin 36°
- A1: 9.9
Answer: 9.9 cm[3 marks] - 2
Question 2. An extra value of 50 is added to the data 4, 6, 7, 9, 10, 12. Work out the interquartile range before and after, and the range before and after.
Benefits of IQR & Range▶ Show worked answerHide worked answer
- B1: IQR before: 10 - 6 = 4 and range 12 - 4 = 8
- B1: IQR after (4, 6, 7, 9, 10, 12, 50): 12 - 6 = 6 and range 50 - 4 = 46
Answer: IQR: before 4, after 6; range: before 8, after 46[2 marks] - 3
Question 3. 3(n + 2) + k(n + 9) is a multiple of 7 for all integer values of n.
k is a positive integer less than 7.
Work out the value of k.Proof with Multiples▶ Show worked answerHide worked answer
- M1: 3n + 6 + kn + 9k = (3 + k)n + 6 + 9k
- M1: 3 + k is a multiple of 7
- A1: k = 4
Answer: k = 4[3 marks] - 4
Question 4. Expand and simplify (2 + √3)(5 - √3)
Expanding Brackets with Surds▶ Show worked answerHide worked answer
- M1: four terms 10 - 2√3 + 5√3 - 3
- A1: 7 + 3√3
Answer: 7 + 3√3[2 marks] - 5
Question 5. A=x : 3(x-2)<12, x is an integer and B=x : x ≥ -1, x is an integer. Work out n(A cap B).
Sets & Inequalities▶ Show worked answerHide worked answer
- M1: x-2<4, so x<6
- M1: A cap B=-1, 0, 1, 2, 3, 4, 5
- A1: 7
Answer: 7[3 marks]