Mixed Topic Worksheet Grades 6/7: Day 014
- 1
Question 1. Decrease 650 kg by 12%.
Percentage Multipliers▶ Show worked answerHide worked answer
- M1: 100 - 12 = 88%
- M1: 650 × 0.88
- A1: 572
Answer: 572 kg[3 marks] - 2
Question 2. Prove that (n + 4)(n + 6) - n(n + 10) is a multiple of 6 for all integer values of n.
Proof with Multiples▶ Show worked answerHide worked answer
- M1: n² + 6n + 4n + 24 - (n² + 10n)
- M1: 24 after the terms in n cancel
- C1: 24 = 6 × 4, which is a multiple of 6
Answer: 24 = 6 × 4[3 marks] - 3
Question 3. The table shows the number of pets owned by 20 pupils. Work out the range and the interquartile range.
Benefits of IQR & Range▶ Show worked answerHide worked answer
- M1: lower quartile (5th to 6th value) =1; upper quartile (15th to 16th value) =2
- A1: range =4
- A1: IQR =1
Answer: Range 4, interquartile range 1[3 marks] - 4
Question 4. Triangle XYZ has angle YZX = 72^°, XZ = 8.5 cm and YZ = 15 cm
Work out its area.
Give your answer to 1 decimal place.Calculating Area Using ½ab sin C▶ Show worked answerHide worked answer
- M1: 1/2 × 15 × 8.5 × sin 72^°
- A1: 60.6
Answer: 60.6 cm²[2 marks] - 5
Question 5. A ball is thrown upwards. Its height, h metres, above the ground after t seconds is given by h = 18t - 6t²
Work out the greatest height of the ball above the ground.Turning Points of Quadratics▶ Show worked answerHide worked answer
- M1: the greatest height is at t = 18 / 12 = 1.5, halfway between the times at which h = 0
- M1: 18 × 1.5 - 6 × 1.5²
- A1: 13.5 metres
Answer: 13.5[3 marks]
Mixed Topic Worksheet Grades 6/7: Day 014
- 1
Question 1. Decrease 650 kg by 12%.
[3 marks]Percentage Multipliers▶ Show worked answerHide worked answer
- M1: 100 - 12 = 88%
- M1: 650 × 0.88
- A1: 572
Answer: 572 kg - 2
Question 2. Prove that (n + 4)(n + 6) - n(n + 10) is a multiple of 6 for all integer values of n.
[3 marks]Proof with Multiples▶ Show worked answerHide worked answer
- M1: n² + 6n + 4n + 24 - (n² + 10n)
- M1: 24 after the terms in n cancel
- C1: 24 = 6 × 4, which is a multiple of 6
Answer: 24 = 6 × 4 - 3
Question 3. The table shows the number of pets owned by 20 pupils. Work out the range and the interquartile range.
[3 marks]Benefits of IQR & Range▶ Show worked answerHide worked answer
- M1: lower quartile (5th to 6th value) =1; upper quartile (15th to 16th value) =2
- A1: range =4
- A1: IQR =1
Answer: Range 4, interquartile range 1 - 4
Question 4. Triangle XYZ has angle YZX = 72^°, XZ = 8.5 cm and YZ = 15 cm
[2 marks]
Work out its area.
Give your answer to 1 decimal place.Calculating Area Using ½ab sin C▶ Show worked answerHide worked answer
- M1: 1/2 × 15 × 8.5 × sin 72^°
- A1: 60.6
Answer: 60.6 cm² - 5
Question 5. A ball is thrown upwards. Its height, h metres, above the ground after t seconds is given by h = 18t - 6t²
[3 marks]
Work out the greatest height of the ball above the ground.Turning Points of Quadratics▶ Show worked answerHide worked answer
- M1: the greatest height is at t = 18 / 12 = 1.5, halfway between the times at which h = 0
- M1: 18 × 1.5 - 6 × 1.5²
- A1: 13.5 metres
Answer: 13.5
Mixed Topic Worksheet Grades 6/7: Day 014
- 1
Question 1. Decrease 650 kg by 12%.
Percentage Multipliers▶ Show worked answerHide worked answer
- M1: 100 - 12 = 88%
- M1: 650 × 0.88
- A1: 572
Answer: 572 kg[3 marks] - 2
Question 2. Prove that (n + 4)(n + 6) - n(n + 10) is a multiple of 6 for all integer values of n.
Proof with Multiples▶ Show worked answerHide worked answer
- M1: n² + 6n + 4n + 24 - (n² + 10n)
- M1: 24 after the terms in n cancel
- C1: 24 = 6 × 4, which is a multiple of 6
Answer: 24 = 6 × 4[3 marks] - 3
Question 3. The table shows the number of pets owned by 20 pupils. Work out the range and the interquartile range.
Benefits of IQR & Range▶ Show worked answerHide worked answer
- M1: lower quartile (5th to 6th value) =1; upper quartile (15th to 16th value) =2
- A1: range =4
- A1: IQR =1
Answer: Range 4, interquartile range 1[3 marks] - 4
Question 4. Triangle XYZ has angle YZX = 72^°, XZ = 8.5 cm and YZ = 15 cm
Work out its area.
Give your answer to 1 decimal place.Calculating Area Using ½ab sin C▶ Show worked answerHide worked answer
- M1: 1/2 × 15 × 8.5 × sin 72^°
- A1: 60.6
Answer: 60.6 cm²[2 marks] - 5
Question 5. A ball is thrown upwards. Its height, h metres, above the ground after t seconds is given by h = 18t - 6t²
Work out the greatest height of the ball above the ground.Turning Points of Quadratics▶ Show worked answerHide worked answer
- M1: the greatest height is at t = 18 / 12 = 1.5, halfway between the times at which h = 0
- M1: 18 × 1.5 - 6 × 1.5²
- A1: 13.5 metres
Answer: 13.5[3 marks]